Apron feeder can be divided into heavy, medium and light apron feeder, which featuring in large granularity ， bulk density and delivery capacity of conveying material, generally above 600U h. This also determines the sufficient strength of the heavy plate feeder itself including rack, chain plate, tart rail, spindle device and tail shaft device. In addition, the calculation of driving power must be sufficient. If too large , the cost will increase therefore the accurate calculation of driving power is particularly important.
So first let's talk about the power calculation of the heavy apron feeder(hereinafter referred to as feeder) . The calculation method of power is as follows:
In fact, the above formula is suitable for calculating the power of the feeder when it is running horizontally. We assume that the feeder is arranged on a slope with an Angle of α. The traction force F must overcome the sliding force caused by the material and the friction force against the positive pressure of the chain plate in order to transport the material to the upper process section. Therefore F=G• sinα+G• ·μ .The unit is kg. F.
N=F·V/102η1·η2=G·﹙sina+cosa•u﹚·V/102η1·η2 (1)
μ: friction coefficient between transported material and chain plate (generally 0,7);
V: chain board speed, unit m/s;
G:Total weight of material on the feeder chain board, unit kg.f;
η1:The use efficiency of the feeder chain board (generally 0·8);
η2:Feeder drive system efficiency (generally 0·8);
G=B、•h•L•y (2)
B、:The actual width of conveying material, unit m, generally take (B-O.1)m,B is the inner width of chain plate
h:Thickness of material layer to be transported, unit m
L:Length of the layer on the feeder, unit m
Y: Bulk density, that is, the density of materials under natural accumulation is also called false specific gravity, unit kg/m3
At the time of α = 0 °,
(1).jpg "Apron Feeder")
N=G•cosa•u•V/102η/1 ·η2,
Formula N: P • V •G/102 · 2
Equation (1) is the real general formula, while Equation (3) is only a special case for the horizontal layout of the feeder during calculation.
Because Q=3600 • V • B, • H •Y/1000=3 ·6V ·B, · H •Y unit: t/h (4)
In the formula, V, B, H. have the same meanings as mentioned in (1).
If the conveying capacity of the feeder required by the user is known, Formula (1) can be further deformed (at the same time, Formula (2) can be substituted by Formula (1)).
According to Formula (4), V = Q/3.6·B,·h·y (5)
Substitute Equation (2) and (5) into Equation (1) to obtain
N=Q · L·(sina+cosa · u) / 102·3.6 ·η 1·η2 (6)
It can be concluded from Equation (6) that the driving power of the feeder is only related to the conveying capacity, the length of the material layer on the feeder and the inclination Angle of the feeder. That is to say, as long as the three values are given, the feeder drive can be quickly determined, and these three values, are the original given design number.
The driving power is deduced by the above formula (6), and a relatively simple algorithm is obtained.
According to the above calculation, we have a basic framework, so that we can design and select the apron feeder. The HENAN EXCELLENT MACHINERY CO.,LTD is a professional bulk material conveying equipment manufacturer. We have professional production capacity and rich production experience as well as strict product quality inspection . We can guarantee that every equipment we produced is qualified equipment, and we ensure the qualified rate of the products. To know more about our products, Please visit our official website: https://www.exctmach.com/.
